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How do you prove this? Any ideas?
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This follows from the fact that
I've got a proof of that lying around somewhere, if you need it.
Why did the vector cross the road?
It wanted to be normal.
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Let
be a common divisor of and and consider the multiplicative group modulo . Since and , divides and . where is the order of 2 in the group. Hence divides and so .Conversely, if
, then divides and so divides and (since divides both and ) and so and .I have shown that every common prime divisor of
and divides and every prime divisor of divides both and . I thus conclude that .Offline