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#1 2009-09-13 08:07:07
- finitehelp
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- Registered: 2009-06-21
- Posts: 80
discontinuous
Find all values x = a where the function is discontinuous.
f(x)=x^2-36/x+6
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#2 2009-09-13 08:41:40
- luca-deltodesco
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- Registered: 2006-05-05
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Re: discontinuous
do you mean:
(x^2-36) / (x+6)
or:
x^2 - 36/x + 6
or:
x^2 - 36/(x+6)
or something else?
without brackets, or any form of formatting it is impossible to know.
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#3 2009-09-13 08:44:51
- finitehelp
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Re: discontinuous
there are no brackets
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#4 2009-09-13 08:47:02
- finitehelp
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- Registered: 2009-06-21
- Posts: 80
Re: discontinuous
I though the answer was -6 but i am not sure
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#5 2009-09-13 08:55:40
- mathsyperson
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- Registered: 2005-06-22
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Re: discontinuous
Well, if there are no brackets then it means this:
In which case, it's discontinuous at x=0.
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It wanted to be normal.
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#6 2009-09-13 09:05:44
- finitehelp
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Re: discontinuous
im sorry this is it
f(x)=(x^2-36) / (x+6)
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#7 2009-09-13 12:09:17
- bobbym
- bumpkin
- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 109,606
Re: discontinuous
Hi finitehelp;
That has a discontinuity at x = - 6
Check this page. 2 / 3 of the way down is a problem exactly like yours.
http://www.worsleyschool.net/science/fi … tions.html
Last edited by bobbym (2009-09-13 12:44:37)
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