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1. x and y are two natural numbers such that 3x^2 + x = 4y^2 +y . Prove that x - y is the square of a whole nnumber rate this problem from 0 to 10 and tell ur soloution
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Thanks for the puzzle, juki.
Oh, and kyle, I just added the "∈" up top, so you can use that if you want
(BTW kylekatarn is confirming: "is x and y a Natural Number {1,2,3,4,...} and is n an integer {... -3, -2, -1, 0, 1, 2, 3, ...} ?")
Let's plug in some numbers just to get this started:
x=1: 3x^2 + x = 4y^2 +y becomes 5 = 4y^2 +y
4y^2 +y - 5 = 0 has the solutions 1 and -1.25
Now, -1.25 is not included because y should be a Natural Number, so we are left with
x=1, y=1, and x-y=0, so I suppose 0 is the square of 0, so that is a good start.
"The physicists defer only to mathematicians, and the mathematicians defer only to God ..." - Leon M. Lederman
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x and y are two natural numbers such that 3x^2 + x = 4y^2 +y
Put x=2,
we get 4y² + y - 14 = 0, Solving,
we get y = [-1 ± √(1 + 224)] / 8
y = -2 or 1.75
Neither of them are Natural Numbers!
x - y is NOT always a square of a natural number
Last edited by Jai Ganesh (2005-07-31 21:02:11)
It appears to me that if one wants to make progress in mathematics, one should study the masters and not the pupils. - Niels Henrik Abel.
Nothing is better than reading and gaining more and more knowledge - Stephen William Hawking.
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Let's plug in some numbers just to get this started:
x=1: 3x^2 + x = 4y^2 +y becomes 5 = 4y^2 +y
When we put x=1,
3x² + x = 3(1² ) + 1 = 4
Therefore,
4y² + y - 4 = 0
y = [-1 ± √ (1 + 64)]/8 = [-1 ± √ 65 ]/8
which is an irational number.
We see that here too x-y is not the square of a natural number
It appears to me that if one wants to make progress in mathematics, one should study the masters and not the pupils. - Niels Henrik Abel.
Nothing is better than reading and gaining more and more knowledge - Stephen William Hawking.
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Put x=2,
we get 4y² + y - 14 = 0, Solving,
we get y = [-1 ± √(1 + 224)] / 2
y=[-1 ± √(1 + 224)]/8, actually. That means that y=-2 or 1.75 and the original proof wanted x and y to both be natural, meaning that these values are disregarded. The same applies to your second post where x=1. Sorry!
Why did the vector cross the road?
It wanted to be normal.
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Corrected the post; thanks, Mathsyperson.
It appears to me that if one wants to make progress in mathematics, one should study the masters and not the pupils. - Niels Henrik Abel.
Nothing is better than reading and gaining more and more knowledge - Stephen William Hawking.
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