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I am trying to prove:
,by using the method where if given any negative number M, we can find a number
such that satisfies if .So we begin with
and .The text gives an answer of
.I can't quite get this to work out and feel that the signs are giving me some trouble. Can anyone show me what's happening here?
Cheers.
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I have tried to solve it this way:
which is different than
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M is negative, it should be
Not
Last edited by TheDude (2009-11-06 05:06:16)
Wrap it in bacon
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OK, so if you just use an unsigned M...
As soon as I try to take the square root (twice) of
Don't I have a problem since I can't come up with a real value for a negative number? If the -1 and M cancel out the negatives, how do I arrive at an answer of
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It's been stipulated that M < 0, so
Wrap it in bacon
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I agree with this also, though I don't know how to arrive at the final answer posted above: 1 / (-M)^1/4. Can you show me how you would solve?
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Wrap it in bacon
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OK, thank you. I guess I am just having trouble with the signs when raised to a fractional power, but this helps me to understand a little better. Watch this space - I'm sure that there will be more questions.
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I know you are happy to find the answer.:)
Happy as happy can be.
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