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Can anyone help me proving that
thanks
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By Lagrange Identity,
Last edited by simplyjasper (2009-11-22 00:35:02)
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Hi identity and simplyjasper;
That's what I am looking at but am having a little problem finishing up.
If you go here and about 1 / 4 of the page down you will find the paragraph "Lagrange's identity and vector calculus"
http://en.wikipedia.org/wiki/Lagrange%27s_identity
I am having a little trouble manipulating their identities to look like your problem.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Yes, that's also what I had trouble with. It was a homework question for a calculus class that I attended (but wasn't enrolled in). I don't think it should involve complicated algebra since it was only for first year calculus.
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Hi identity;
I think when you square the LHS of your problem you should get:
(a x b)² I don't understand how they get the dot product in there (a x b) (a x b)
Also look at this:
http://answers.yahoo.com/question/index … 850AA83WT7
Last edited by bobbym (2009-11-22 00:58:52)
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Isn't it just by using the identity and taking away from both side
(a . b)^2
Or you need to prove the identity before you can use it?
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Hi simplyjasper;
Yes, that would work, unless they want him to prove that identity that you are quoting.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Thanks bobbym, that's what I was looking for
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