Math Is Fun Forum

Karn

Member

Registered: 2009-11-15

Posts: 14

another Indices question

Hello

How do find the value of n in the following

(1+n/8)^2 = 1 17/64

I fist converted the fraction into a improper fraction and used the 'power of a quotient law' but then I was stuck.

Thank you for any help

Last edited by Karn (2009-12-21 18:14:20)

bobbym

bumpkin

From: Bumpkinland

Registered: 2009-04-12

Posts: 109,606

Re: another Indices question

Hi Karn;

Times both sides by 64:

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In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.

Inna

Guest

Re: another Indices question

[(8+n)/8]^2=81/64
(8+n)^2/64=9^2/64
*64 both sides
(8+n)^2=9^2
8+n=9 or 8+n=-9
n=1 or n=-17

soroban

Member

Registered: 2007-03-09

Posts: 452

Re: another Indices question

.

Last edited by soroban (2009-12-22 09:43:57)