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somehow I feel that this problem's information is very insuffient, but I guess any set containing p+q can be eliminated.
the answer is e.
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What I find a bit interesting is that the module structure of an abelian group doesn't add any information, but makes the above proposition more straightforward.
"In the real world, this would be a problem. But in mathematics, we can just define a place where this problem doesn't exist. So we'll go ahead and do that now..."
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sorry for the late reply, what I dont understand is that it seems to be a group of under module something but it doesnt say anything
hmm that's an interesting proposition, first I doubted it because I overlooked the requirement that G is a group itself
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Use Bézout's identity to prove the proposition.
"In the real world, this would be a problem. But in mathematics, we can just define a place where this problem doesn't exist. So we'll go ahead and do that now..."
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