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Someone please help me... I don't even understand.
1. Give an example of group G and two subgroup A, B of G such that AB is a subgroup of G
2. Prove that (1 2) cannot be written as the product of disjoint 3 cycles
3. 1. if G has no proper subgrup, prove that G is cyclic
4. Express as the product of disjoint cycles and find the order
a. (1 2 3 5 7) (2 4 7 6)
b. (1 2) ( 1 3) ( 1 4)
c. (1 2 3 4 5) ( 1 2 3 4 6) (1 2 3 4 7)
d. ( 1 2 3) (1 3 2)
I would be very thankful if someone could help me..please...
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1. Hint: consider making A a subgroup of B.
3. If
and , what is ?4. I will show you my own example so you can do yours. Consider
. Work from right to left. Under this permutation:So 1 maps to 3 and 3 maps back to 1, while 2 maps to 5 and 5 maps back to 2. Hence the permutation in disjoint cycles is
. You get the idea, hopefully.The order of a product of disjoint cycles is the LCM of the lengths of the cycles.
Last edited by JaneFairfax (2010-02-10 00:05:09)
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