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#1 2010-02-20 07:23:15

iamfriendly
Member
Registered: 2009-07-03
Posts: 72

Probability related.....probably

Say 2 indentical bags contain different numbers of swear and tongue counters.
A bag is chosen AT RANDOM and a single counter removed from it without looking.

bag A : 2swear   3tongue

Bag B : 3 swear 4tongue



If the counter was swear what was the probability that the bag was Bag A?? dunno


EYE AM FRIENDLY, THAT'S O U NEED 2 NO,
psst,
Don't trust strangers, EYE AM FRIENDLY, THAT'S O U NEED 2 NO ..........psst, Don't trust strangers......

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#2 2010-02-20 07:35:23

iamfriendly
Member
Registered: 2009-07-03
Posts: 72

Re: Probability related.....probably

I got
2     any different anwsers? please HELP
5


EYE AM FRIENDLY, THAT'S O U NEED 2 NO,
psst,
Don't trust strangers, EYE AM FRIENDLY, THAT'S O U NEED 2 NO ..........psst, Don't trust strangers......

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#3 2010-02-20 10:44:16

mathsyperson
Moderator
Registered: 2005-06-22
Posts: 4,900

Re: Probability related.....probably

The probability of choosing bag A, then getting a swear from it is 1/2 * 2/5 = 1/5.
The probability of choosing bag B, then getting a swear from it is 1/2 * 3/7 = 3/14.

The overall probability of getting a swear is the sum of these two, which is 29/70.

Therefore, given that you picked a swear, the probability of you having chosen bag A is
(1/5) / (29/70) = 14/29.


Why did the vector cross the road?
It wanted to be normal.

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#4 2010-02-27 12:33:13

iamfriendly
Member
Registered: 2009-07-03
Posts: 72

Re: Probability related.....probably

Thank you very much


EYE AM FRIENDLY, THAT'S O U NEED 2 NO,
psst,
Don't trust strangers, EYE AM FRIENDLY, THAT'S O U NEED 2 NO ..........psst, Don't trust strangers......

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