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1) Ten divided by the difference of a number and one equals the quotient of the number and two.
2) The ratio of six and a number squared, reduced by one, is equal to the reciprocal of the number.
Thank you for your time.
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1.
2.
Why did the vector cross the road?
It wanted to be normal.
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Thanks. I hate English in my Math
I solved the first problem but the second I ran into a snag.
I used 6X as the LCD which resulted in
x^3-6x=6
x^3-6x-6=0
I cannot factor that any lower. Did I do something wrong?
Last edited by Slowlrnr (2010-03-31 11:06:57)
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2.
it should be....
If two or more thoughts intersect, there has to be a point!
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Thanks.
Unfortunately, I have another issue with a word problem. I stink at these.
A tub takes three times as long to fill now that it has sprung a leak than it did before. All of the water will leak out of the tub in 1 hour. How long does it take the tub to fill with and without the leak?
Alright, I think I determined the formula "without the leak" to be:
1/T-1/60=1/(3T) and it came out to 40 minutes.
or should I have expressed this as
1/T-1/(3T)=1/60
I am having an issue with the "with the leak" setup.
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