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I just thought of this question:
Scenario:
There are 350 people attending a celebration dinner.
Seated at every table are 10 people (35 tables).
One of the event is a lucky draw with 35 prizes to be given out by drawing numbers electronically.
Assumptions (if necessary):
1) Nobody can get a prize twice.
2) Everybody stays until the end of the event.
3) The drawing of the numbers is fair.
Question:
1) What is the chance that a person gets a prize?
2) What is the chance that at least one person from a table gets a prize?
3) What is the chance that everybody from a table gets a prize?
Anybody can help me? Please show your working and answers clearly documented.
Last edited by samliew (2005-08-28 11:47:31)
Personal Website: www.samliew.com
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1) 35/350=0.1
2)Chance that nobody gets a prize -- 0.9^10=0.34867844
Chance that at least one person gets a prize-- 1-0.34867844=0.65132156
3) 0.1^10=1.0 × 10-10 (which is very low)
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Neat job, wcy !
And a big welcome to the forum, samliew.
"The physicists defer only to mathematicians, and the mathematicians defer only to God ..." - Leon M. Lederman
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Thanks alot! Actually, I was in that dinner
Personal Website: www.samliew.com
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