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1) (x² + 2)² ÷ (x² + x-¹)³
2) (x² + 1)² (x³ - 2x)²
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Hi Joker;
We can start with 2) first:
We have already covered a lot of this in the previous posts. I showed you the general methods that you need to know. First, have you tried this:
That is the formula for the diff. of a product. Please show me what you have done so far so I can see what you didn't understand from yesterday.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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hey,
Do i expand the brackets before i differentiate?
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Hi Joker;
If that is the only idea you have then that's okay. Any answer is better than no answer at all. At least you can get partial credit if you try something. Show me what you get and we will go from there.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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f(x)= (x^2-2)^2 f(g)= (x^3-2x)^2
= (2x^4-4) = (2x^5-8x^2)
(2x^4-4)(10x^4-16x) + (2x^5-8x^2)(8x^3)
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Hi Joker;
(x^2 - 2)^2 doesn't equal (2x^4 - 4). Show me how you multiplied it.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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ooo
how about this?
(x^2-2)(x^2-2)
2x^4-2x^2-2x^2+4
2x^4-4x^2+4
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Hi Joker;
That is not quite correct either. Try the foil method.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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x^4-4x^2+4 ? am i getting close?
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Hi Joker;
That is correct! Now if you are determined to expand it before differentiating it then please do that now. Will be back in a little while, going to eat.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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f(x) = x^4-4x^2+4 g(x) = x^6-4x^3+4x^2
d [f(x)g(x)] = (x^4-4x^2+4)(6x^5-12x^2+8x) + (4x^3-8x)(x^6-4x^3+4x^2)
i think i know what to do now
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would it be the same way differentaiting the function above as this (3x + 5)^10 function?
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Hi Joker;
Did you get this for your expansion?
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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