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A class contains 10 men and 20 women of which half the men and half the women
have brown eyes. Find the probability that a person chosen at random is a man or has
brown eyes.
Solution:
P(Man)=10/30=.33
P(Brown)=15/30=.5
P(M intersect B)=5/30= .166
P(MUB)=P(M)+P(B)-P(M intersect B)
P(MUB)= .33 + .5 - .166
P(MUB)= .664 Ans
If solution wrong kindly guide me
Last edited by NESIC (2010-10-09 05:55:43)
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Hi NESIC;
Use your Venn diagrams while learning! Click the picture below.
P(M) = 1/3
P(B) = 1/2
We would like to just add them up like this.
But you counted the intersected area twice (see the drawing )! So take one of them away.
The formula is easily derived from the diagram.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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