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I was not trying to pose a tough question for him. He asked for a couple of problems. I gave him problems that illustrate the method. I did not claim that it was the best method or the only method for those problems. And again, he had no choice.
It was not a race to find the shortest 1 line proof possible.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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my friend i check ans is squt5
this is "AIEEE" 2007 question
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I am sorry, but the answer is not the √5
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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squt(5) is ans of max(x+2y)
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Are not we talking about this one?
Maximize 3x - y - 3z Subject to:
He got the right answer too. So why is yours an improvement over his?
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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squt(24) is answer of max(3x-y-3z)
both are true I check your lagrange multiplier method
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Okay, but it is not my method, otherwise it would be called the Method of bobbym Multipliers. I mean I would like that better but do you think we could get the rest of the math community to buy that?
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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what is natural log of squt(-1)
if know then reply please
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Hi sameer;
And please let us keep this thread for the discussion of inequalities, not for attempts to prove I am a dummy.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Hi Sameer,
Bobby was just teaching me a new optimisation tool called the Method of Lagrangian Multipliers.
Your method is also good.
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Hi;
I do not think the concept of using this "method" is seeping into his mind.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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hello friend.........
find max,min (3x+2y+5z)
if[x^2+y^2+z^2]=45
Last edited by sameer mishra (2010-12-09 18:29:36)
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if x,y,z are sides of a triangle R is radius of circumcircle A is area of triangle
then prove that
log(A)+log(4)+log(R)>=3(log(x)*log(y)*log(z))^1/3
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what is maximum $minimum valu of 1/(3-5cosx)
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If you want to pose problems put them in the Exercises thread. Learn how to start a new thread or ask and I will show you.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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sorry friend in 1/(3-5cosx) you are wrong
CORRECT ANS
the denominator 3-5cosx=0 ->cosx=3/5 which is in the region [-1 1]
hence correct range is(-∞ -1/2]U [1/8 ∞)
hence you can see wht is max$min
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max$min(3x+2y+5z)
Let ->
A=Xi+Yj+Zk
B=3i+2j+5k
A.B=mod(A)mod(B) cos (t) "max if cos(t)=1,min if cos(t)=-1"
3x+2y+5z=squrt(x^2+y^2+z^2)*squrt(38) cos(t)
put valu of x^2+y^2+z^2=45 $get ans
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Hi;
All that up there is very hard to read. There are a couple of syntax errors. You have forgotten commas and what is $?. Also you have no answers that I can see.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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