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How there can be simultaneously these three formulas:
Probably, correctly so:
Last edited by mishin05 (2010-12-25 12:05:58)
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hi mishin05
I don't think they are all true.
(i) Looks ok to me.
(ii) I think you are assuming that if two integrals are equal, then so are the functions.
(iii) I cannot follow your first line. Please check it. Either explain or correct it. Thanks.
Bob
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you! …………….Bob
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hi mishin05
I don't think they are all true.
(i) Looks ok to me.
(ii) I think you are assuming that if two integrals are equal, then so are the functions.
(iii) I cannot follow your first line. Please check it. Either explain or correct it. Thanks.
Bob
Hi, Bob
(ii) - The zero integral can't give number!
(iii) -
Last edited by mishin05 (2010-12-26 02:33:44)
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hi mishin05
(ii) Maybe I've changed my mind. What's wrong with integral of zero = 0 ?
(iii) but dU = 0 so you're just left with integral of 1 = x. That's ok too.
Don't think you should write dU = d1 though.
So all three are not mutually contradictory.
Bob
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you! …………….Bob
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Greetings, Bob!
But how to be what conclusions 2 and 3 contradicts a conclusion 1?
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hi mishin05
The correct 'formula' for (iii) is
If you put U = x and V = 1 then
That looks ok to me.
Bob
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you! …………….Bob
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