Inverse z-transform

Onyx · 2010-12-31 05:51:35

I have a transfer function:

I can't find it in any transform table. Is it possible to use a convolution sum to solve this from inverse z-transforms of its constituent factors? I can't find a way to do it. Thanks

bobbym · 2010-12-31 06:54:06

Hi Onyx;

Looks like a Z transform. You have to use the inverse Z transform on it. The answer is going to involve the unit step function, which is a piecewise function.

Onyx · 2011-01-01 04:42:23

Thanks, I know I need to use inverse z transform, but I can't find anything in a z-transform table, so I'm not sure how to do it.

bobbym · 2011-01-01 04:47:22

Hi Onyx;

If you are looking for a method, there are a couple of them ( all of which I have forgotten ) but like a Laplace transform you usually end up using a table of them anyway. I can provide the answer but as I said it involves the Unit step function ( Heaviside function ). It is a discontinuous function. That is the reason it is not in standard tables.

Onyx · 2011-01-01 04:55:24

Well most the tables I have looked at actually do define the inverse transforms in terms of the unit step, and the unit impulse (Kronecker delta) functions, which is expected, since it represents causality of the discrete time systems I'm working with. I think I mayu need partial fractions...

bobbym · 2011-01-01 04:58:37

Hi Onyx;

That is one way of putting it into a form that a table will have. Just holler if you need the answer.

Math Is Fun Forum

#1 2010-12-31 05:51:35

Inverse z-transform

#2 2010-12-31 06:54:06

Re: Inverse z-transform

#3 2011-01-01 04:42:23

Re: Inverse z-transform

#4 2011-01-01 04:47:22

Re: Inverse z-transform

#5 2011-01-01 04:55:24

Re: Inverse z-transform

#6 2011-01-01 04:58:37

Re: Inverse z-transform

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