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hi guys, so i understand that the product rule can be applied
when finding dy/dx for-
y=f(x)g(x)
then dy/dx=f'(x)g(x)+g'(x)f(x)
but what happens if you are trying to find dy/dx for
y=f(x)f(u)
where u is a function of x as well?
for example y=f(x) (ln g(x))
do you use chain rule or is it just the same thing?
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hi nevinsmith
You will have to use both the product rule (first) but also the chain rule when you come to
Example.
First product rule
Looking this over, I can see that simplifying the 'ln' would have been easier, but, so what, it's the method you wanted.
Hope that helps.
Post an question if you need further assistance.
Bob
Last edited by Bob (2011-02-11 21:42:05)
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you! …………….Bob
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thanks for your help bobby now i understand!
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hi nevinsmith
You're welcome.
Bob
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you! …………….Bob
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