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hello,
again i am stuck on a question in an S1 past paper.
"3) The events A and B are such that
P(A) = 0.2 and P(A U B) = 0.6
Find
(a) P(A' n B')
(b) P(A' n B)
Given that events A and B are independent, find
(c) P(B)
(d) P(A' U B')
I know that "n" means and, and "U" means or.
i thought that P(B) should be 0.4 because its saying the probability of A OR B occurring so 0.2 + B = 0.6 so B = 0.4. the mark scheme says this is wrong...
can anyone tell me how to do this?
also, i can't do any of the other questions, because i don't know what A' means, or B'...what does the dash/apostrophe mean?
i take it A' means NOT A?
hi mathwonka
Yes A' means not in A
I've put a (Venn) diagram below that shows the four spaces, in A but not B; in both, in B but not A; not in either.
You know that P(A) = 0.2 which includes P(A n B') and P(A n B)
If P(A u B) = 0.6 then taking out the bits in A leaves P(B n A') = 0.4
So P(A' n B') = 0.4 also ( = 1 - 0.2 - 0.4)
Now if the events are independant P(A when B is known to have occurred) = P(A)
So let P(A n B) = x => P(B) = x + 0.4
So P(A when B is known to have occurred) = x / (x + 0.4)
so x/(x + 0.4) = 0.2 => x = 0.1
So you can now fill in the Ps for all four spaces and complete the question.
Bob
Last edited by Bob (2011-02-13 08:52:18)
Children are not defined by school ...........The Fonz
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