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Hello - i have a problem to solve for my homework but i am not sure how to do it. Can anyone tell me how i work this out please.
Jane and John have 48 oranges between them. Jane has 5 times more oranges than John. How many oranges does John have?
Thank you very much,
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hi Cherrydrop
How are you with algebra?
I'd do this problem like this:
Let's say Jane has 'x' oranges. Then John must have (48 - x) oranges. (Takes Janes number from the total of 48.)
Also Jane has 5 times as many so if you take John's number and times by 5 you get Janes number.
5(48-x) = x
Can you solve this? ie find x?
If you cannot do the algebra then trial and improvement will get you to an answer.
eg guess that x = 10. So Jane has 10 and John has 2. But that doesn't add up to 48, so try a bigger guess.
I've just re-read the problem. When you get x, don't forget the question is how many has John got, not Jane.
I did think of re-working the problem starting with "Let's say John has ......" but I think the calculations are a bit harder this way round, so I'm sticking to my first version.
Bob
Last edited by Bob (2011-02-16 07:38:27)
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you! …………….Bob
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Thank you Bob. I didn't think of it as algebra and now that you have said that, i've worked it out as:
1x + 5x = 6x
48 / 6 = 8
John has 8 oranges.
Thank you very much.
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hi CherryDrop
You are welcome.
And I see you made up your own equation. Excellent!! Gold star!
:)
Bob
Last edited by Bob (2011-02-16 09:22:00)
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you! …………….Bob
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