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Hi guys, I'm really stuck on this tricky moments question:
Figure 2 is attached.
Thanks very much .
Last edited by Au101 (2011-03-15 09:18:04)
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hi Au101,
The moment of a force is (the magnitude in Newtons) times (the perpendicular distance from the point to the force) ...{that you are taking moments about}
Another way to think about it is "it's the turning effect of a force".
For the first part the moments are about A. Two forces act through A so the perpendicular distance for those two is zero => no turning effect.
The two remaining act clockwise and anticlockwise so subtract the smaller from the larger.
= 3N x 2m - 2N x 2m = 2 Nm (Newton-metre) in an anticlockwise direction.
For part two the moments are about D, so once again two forces have zero effect.
You are left with
3 x 2 + 5 x 2 - X times √2 (distance from D to the centre of the square)
= 8 x 2 - √2.X = 0
so X = 16/√2 = 16√2 / 2 (multiplying top and bottom by root 2) = 8√2 N
Bob
Last edited by Bob (2011-03-15 11:29:54)
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you! …………….Bob
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Aha, thank you very much yet again Bob. Also, I like your new quote
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hi Au101,
You are welcome.
My daughter has a book full of quotes listed alphabetically by topic. So I had lots that I liked. This was one I particularly liked for this forum. Some were brilliant but not suitable for family viewing!
Bob
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you! …………….Bob
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