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Im trying to find an expression for the limit below. I know a limit exists because I can calculate it in Excel but Id like to find a closed-form version. Any ideas on how to evaluate this?
a: = sum of (1+g)^(i-1) * (1-p)^(n-i), where i=1..n
b:= sum of (1+g)^(i-1), where i=1..n
evaluate limit as n-->infinity of {a/b}
Assume that p and g are constants such that:
0<p<1
-1<g<1
The quotient is essentially a weighted average where the weight factor is (1-p)^(n-i). Larger values of i will have greater weight in the average.
Thanks!
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Hi jhomme;
Is this what we are working on?
Where you want to evaluate the limit.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Yes, indeed! Well done. This is already a huge simplification that can help me quickly approximate the limit using high values of n. That's 99% of what I was looking for.
Just curious, can you point me to some reference material for how you came to these expressions? Especially the one for the numerator.
Thx!
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Hi jhomme;
First things first, for some values of p and g, both a and b will not exist.
For those summations I used Mathematica. Since you wanted the limit, I tried to get to it as fast as possible.
a, is not responding to simple methods but b can be done using the geometric series.
Multiply both sides by the common ratio. ( 1+ g ).
Subtract 1 from 2.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Hi all,
First, let's find a.
Last edited by gAr (2011-06-02 17:46:55)
"Believe nothing, no matter where you read it, or who said it, no matter if I have said it, unless it agrees with your own reason and your own common sense" - Buddha?
"Data! Data! Data!" he cried impatiently. "I can't make bricks without clay."
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Brilliant! Thanks to both bobbym and gAr!
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Your welcome! There is some nice stuff in gAr's solution. Interesting.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Hi jhomme,
You're welcome!
"Believe nothing, no matter where you read it, or who said it, no matter if I have said it, unless it agrees with your own reason and your own common sense" - Buddha?
"Data! Data! Data!" he cried impatiently. "I can't make bricks without clay."
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