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Whick of the following is equal
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When you set them all equal to each other, {A}^{1/A}={B}^{1/B}={C}^{1/C}, can you not conclude that A=B=C?
Last edited by MathPro101 (2011-06-09 05:50:17)
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Hi,
I'm getting:
"Believe nothing, no matter where you read it, or who said it, no matter if I have said it, unless it agrees with your own reason and your own common sense" - Buddha?
"Data! Data! Data!" he cried impatiently. "I can't make bricks without clay."
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9 ^ Abc
ImPo$$!BLe = NoTH!nG
Go DowN DeeP iNTo aNyTHinG U WiLL FinD MaTHeMaTiCs ...
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We can also have:
"Believe nothing, no matter where you read it, or who said it, no matter if I have said it, unless it agrees with your own reason and your own common sense" - Buddha?
"Data! Data! Data!" he cried impatiently. "I can't make bricks without clay."
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also the method
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Hi,
I'm getting:
what is the method used
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Hi,
"Believe nothing, no matter where you read it, or who said it, no matter if I have said it, unless it agrees with your own reason and your own common sense" - Buddha?
"Data! Data! Data!" he cried impatiently. "I can't make bricks without clay."
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dear gAr,
you have taken k as A^1/A ,B^1/B, C^1/C
then how can you write it as k^ABC+ k^ABC+ k^ABC ???
please explain
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hi dev
i'm getting the same as gAr
Last edited by anonimnystefy (2011-06-10 05:16:38)
Here lies the reader who will never open this book. He is forever dead.
Taking a new step, uttering a new word, is what people fear most. ― Fyodor Dostoyevsky, Crime and Punishment
The knowledge of some things as a function of age is a delta function.
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hi
I agree with gAr's analysis. But do A, B and C exist (in real numbers let's say) ?
so
so I plotted the graph of y = logx and the graph of y = x.logk, using 'x' to replace 'A' and trying various values for logk
see graph below.
Either the line fails to hit the curve at all; or it touches as a tangent once; or it crosses twice (which I show with logk = 0.11)
But we also want B and C to have this property so I think this means that if k, A, B and C exist in reals then either
(i) A = B = C
or
(ii) at least a pair are equal, let's say wnlog, B = C
That's it for the moment I'm afraid.
Bob
Last edited by Bob (2011-06-10 06:07:24)
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you! …………….Bob
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hi
I agree with gAr's analysis. But do A, B and C exist (in real numbers let's say) ?
so
so I plotted the graph of y = logx and the graph of y = x.logk, using 'x' to replace 'A' and trying various values for logk
see graph below.
Either the line fails to hit the curve at all; or it touches as a tangent once; or it crosses twice (which I show with logk = 0.11)
But we also want B and C to have this property so I think this means that if k, A, B and C exist in reals then either
(i) A = B = C
or
(ii) at least a pair are equal, let's say wnlog, B = C
That's it for the moment I'm afraid.
Bob
All are wrong ANSWERs
answer is B) {2}^{1/2}
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We can also have:
All are wrong ANSWERs
answer is B) {2}^{1/2}
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"Believe nothing, no matter where you read it, or who said it, no matter if I have said it, unless it agrees with your own reason and your own common sense" - Buddha?
"Data! Data! Data!" he cried impatiently. "I can't make bricks without clay."
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hi gAr
Are you saying that there's a multiplicity of possible values for A, B, C and k? I didn't think we had any yet; in the sense that: we're asked to pick from (a), (b), (c) or (d).
Bob
Last edited by Bob (2011-06-11 01:56:30)
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you! …………….Bob
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Hi Bob,
It's not possible to have real solution if A, B and C are all distinct. But the question mentions nothing about A, B and C!
"Believe nothing, no matter where you read it, or who said it, no matter if I have said it, unless it agrees with your own reason and your own common sense" - Buddha?
"Data! Data! Data!" he cried impatiently. "I can't make bricks without clay."
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hi devkumararora
In post #12 you say
All are wrong ANSWERs
answer is B) {2}^{1/2}
I wasn't offering my analysis as an 'answer'; just a step on the way to an answer (maybe). Are you saying I've made a mathematical mistake ? (entirely possible; I make them all the time; but I need to know what mistake).
Meanwhile you say (b), root 2, is the answer.
Have you some working to support this because I'd like to see it; or just that you have the 'official' answer?
RauLiTo : You offer 9^ABC but again, may I see your working for this?
gAr: Ok it doesn't ask us to state values for A, B, and C ... but I'd rather like to know if values exist. It would be a very curious problem if it were possible to answer the multi-choice, and yet, no actual values for the letters exist. That is, for me, an even harder concept.
Bob
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you! …………….Bob
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Hi Bob,
By symmetry, we must have A^(BC) = B^(AC) = C^(AB) = 243.
And I chose, A^(1/A) = B^(1/B) = C^(1/C) = 243, hoping that there may be many complex solutions for x^(1/x) = 243.
I entered x^(1/x) = 243 into wolframalpha, it answered in terms of ProductLog function.
Don't have anything neat yet!
"Believe nothing, no matter where you read it, or who said it, no matter if I have said it, unless it agrees with your own reason and your own common sense" - Buddha?
"Data! Data! Data!" he cried impatiently. "I can't make bricks without clay."
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hi gAr
I thought I'd try each multi-choice answer and see what values pop out.
But, it's beginning to look like A, B, C will end up complex for all four.
Bob
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you! …………….Bob
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Hi Bob,
Yes, I too think so.
"Believe nothing, no matter where you read it, or who said it, no matter if I have said it, unless it agrees with your own reason and your own common sense" - Buddha?
"Data! Data! Data!" he cried impatiently. "I can't make bricks without clay."
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hi gAr
Using
Consider the graph
So when does
have
as a tangent?
using (1)
see graph
So for real values of A, B, C
when
(a)
when
(c)
when
(d)
when
(b)
So for all four answers k is too big for any real solutions for A, B, and C.
Bob
Last edited by Bob (2011-06-11 21:05:55)
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you! …………….Bob
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Hi Bob,
Thanks for the explanation!
Yes, there can be no real solutions.
I'm unable to find even a complex solution. That k also might be a complex number.
Or is there any solution at all?
"Believe nothing, no matter where you read it, or who said it, no matter if I have said it, unless it agrees with your own reason and your own common sense" - Buddha?
"Data! Data! Data!" he cried impatiently. "I can't make bricks without clay."
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No need to worry my friends
i got the question from one of my books
at back the answer was {2}^{1/2}
I THINK THE QUESTION IS WRONG I THINK IT SHOULD BE
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I Am Having Doubts I A Bunch Of Questions Would You All Solve Them For Me Please
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sure
Here lies the reader who will never open this book. He is forever dead.
Taking a new step, uttering a new word, is what people fear most. ― Fyodor Dostoyevsky, Crime and Punishment
The knowledge of some things as a function of age is a delta function.
Offline
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