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Hi;
To find P you solve the system of equations:
So x = 0 and x = -3
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Thanks a lot bobbym. Didn't see your post at first as it was on page 2. g(x):y=-1/2x so then x=-5 which makes more sense as p<q and q=(-4,0). I totally forgot what to do if I have e.g x^2 +5x. So x(x+5)
x=0 or x=-5
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Hi;
Be careful of those signs: g(x):y=-1/2x.
It is g(x) = x / 2.
x = - 3 and x = 0 not x = - 5. Remember the final equation is x(x+3) = 0.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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