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My question is that, is it any pseudo pattern gives prime number in proper range? If some set of number can give you each and every prime number in fixed range? Range is like this
2 to 4
3 to 9
5 to 25
11 to 121
13 to 169
.
.
.
n to n*n
I have way to find out prime number. It is simple. Most important things is that its not a time taking. Just i will have to subtract a unique set of number from fixed number.
example no 1 ( This give us prime no grater then equal to 11 and less then equal to 121).
210-199=11
210-197=13
210-193=17
210-191=19
210-187=23
210-181=29
210-179=31
210-173=37
210-169=41
210-167=43
210-163=47
210-157=53
210-151=59
210-149=61
210-143=67
210-139=71
210-137=73
210-131=79
210-127=83
210-121=89
210-113=97
210-109=101
210-107=103
210-103=107
210-101=109
210- 97=113
I can find out any prime number.
I have used unique set of number and subtract it from fixed number as in example no 1.
example no 2.( This give us prime no grater then equal to 13 and less then equal to 169)
2310-2297=13
2310-2293=17
2310-2291=19
2310-2287=23
2310-2281=29
2310-2279=31
2310-2273=37
2310-2269=41
2310-2267=43
2310-2263=47
2310-2257=53
2310-2251=59
2310-2249=61
2310-2243=67
2310-2239=71
2310-2237=73
2310-2231=79
2310-2227=83
2310-2221=89
2310-2213=97
2310-2209=101
2310-2207=103
2310-2203=107
2310-2201=109
2310-2197=113
2310-2183=127
2310-2179=131
2310-2173=137
2310-2171=139
2310-2161=149
2310-2159=151
2310-2153=157
2310-2147=163
2310-2143=167.
Sir I can find any prime number of multi digits. But calculating limit of computer do not allow me to work further. So please help me in this regards.
Sir i had already solved so many things in prime number representation is required.
So my request is if possible plz suggest me the platform where i can represent it.
SATISH KUMAR SINGH
GTL NPD PUNE
09011056492
IF there is problem there is solution
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Hi satwnz;
Welcome to the forum.
2310-2179=131
2310-2173=137
2310-2171=139
2310-2161=149
2310-2159=151
2310-2153=157
2310-2147=163
2310-2143=167
The numbers you are using to subtract, how are you creating them?
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Log(N)?
X'(y-Xβ)=0
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Log(N) generates those numbers on the right?
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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The "probability" of N being a prime is
1/ln(N)
And the expected amount of primes within the first N natural numbers is:
Li(x) ≡ ∫ 1/ln(x) dx
proved by
Jacques Hadamard & Charles de la Vallée-Poussin
X'(y-Xβ)=0
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Hi GeorgeY;
I know about that result and there are others.
2310-2173=137
That still does not explain where the 2173 ( along with the rest ) comes from. That is what I hoping to get him to reveal.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Ah I see, that's an interesting conjecture.
satwnz you can try publishing it.
X'(y-Xβ)=0
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Hi all;
I do not think we are going to get any answers from the OP.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Hi satwnz;
Welcome to the forum.
2310-2179=131
2310-2173=137
2310-2171=139
2310-2161=149
2310-2159=151
2310-2153=157
2310-2147=163
2310-2143=167The numbers you are using to subtract, how are you creating them?
Hi it is well define sets of number .........and can go for larger number also..........but my laptop support to 15 digits only.
IF there is problem there is solution
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Hi GeorgeY;
I know about that result and there are others.
2310-2173=137
That still does not explain where the 2173 ( along with the rest ) comes from. That is what I hoping to get him to reveal.
In fact i am researching in field of prime number pattern..........and number u hd underlied is element of welldfine set.
IF there is problem there is solution
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Ah I see, that's an interesting conjecture.
satwnz you can try publishing it.
really...........will u help me.
IF there is problem there is solution
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Hi satwnz;
Welcome to the forum.
2310-2179=131
2310-2173=137
2310-2171=139
2310-2161=149
2310-2159=151
2310-2153=157
2310-2147=163
2310-2143=167The numbers you are using to subtract, how are you creating them?
how are you creating them...........There two step algo to fin it.If u r intrested in it plz contact me on [email removed by moderator]
IF there is problem there is solution
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Hi satwnz;
For your own protection please do not leave your email address lying around like that.
Anyways, is there any reason why you can not post your work right here?
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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I see that 210 = 2*3*5*7
And I see that 2310 = 2*3*5*7*11
But, for instance, the numbers in the list
that are being subtracted from 210 are
not all prime numbers. I feel that the numbers
in your list are presupposed, that you are
partially putting the cart before the horse
(or at least sideways to the cart).
Signature line:
I wish a had a more interesting signature line.
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Ipn series Range of continues Prime No of Ipn sub series Common difference % of Ipn element w.r.t. + Ve integer
I2 2 ≤ P < 4 1 2 100%
I3 3 ≤ P < 9 1 2 50%
I5 5 ≤ P < 25 2 6 33.33%
I7 7 ≤ P < 49 8 30 22%
I11 11 ≤ P < 121 48 210 20%
I13 13 ≤ P < 169 480 2310 19%
I17 17 ≤ P < 289 5760 30030 18%
I19 19 ≤ P < 361 92160 510510 17%
.
.
.
.
IpN................
Ex-I3 have one AP Serie and C.d = 2
3, 5, 7, 9, 11, 13------∞
i) Contain all rpimes and specific odd positive integer from 3 to infinite
ii) Continious prime 3≤P<9
ii) I3 Contain only 50.00% of positive integer
Ex-I5 have two AP Serie and C.d = 6
5 11 17 23 29 35 41 ------∞
7 13 19 25 31 37 43 -----∞
i) Contain all prime and specific odd positive integer from 5 to infinite
ii) Continuous prime 5≤P<25
ii) I5 Contains only 33.33% of positive integer
IF there is problem there is solution
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PREVIOUS POST WAS APPLICATION OF PATTERN ONLY
IF there is problem there is solution
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You have a list of prime numbers in the far left column,
where they are being used for analysis/calculations.
It looks as though you have to have those prime numbers
in advance to get a longer list of greater prime numbers.
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I wish a had a more interesting signature line.
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You have a list of prime numbers in the far left column,
where they are being used for analysis/calculations.It looks as though you have to have those prime numbers
in advance to get a longer list of greater prime numbers.
Ipn series--- It is well define set of posative number.
Range of continues Prime ----It contains each and every prime number in fixed range.
No of Ipn sub series...This Ipn series have subseries it is also well define.
Common difference......As subseries are in A.P so common difference is given
% of Ipn element w.r.t. + Ve integer........it %of Ipn series wrt posative integer.i.e how many Ipn are in set of all +ve integer
Ex-I3( it is Ipn series) have one AP Serie and C.d = 2
3, 5, 7, 9, 11, 13------∞
i) Contain all primes and specific odd positive integer from 3 to infinite
ii) Continious prime 3≤P<9
ii) I3 Contain only 50.00% of positive integer
Ex-I5( it is Ipn series) have two AP Serie and C.d = 6
5 11 17 23 29 35 41 ------∞ (sub series 1)
7 13 19 25 31 37 43 -----∞ (sub series 2)
i) Contain all prime and specific odd positive integer from 5 to infinite
ii) Continuous prime 5≤P<25
ii) I5 Contains only 33.33% of positive integer
like this we can go for any series and any prime number.
br//
satish
IF there is problem there is solution
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Hi satwnz;
You say that it is not time consuming. But I think you mean just for small numbers.
Is 1 111 111 111 111 111 111 a prime? What do you subtract from this to know?
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Hi satwnz;
You say that it is not time consuming. But I think you mean just for small numbers.
Is 1 111 111 111 111 111 111 a prime? What do you subtract from this to know?
I hv deal wit max 15 digit number.But i can go for n digit numer if some supportive system is with me.
if it is well define for numer up to 15 digit We sure it will give posative result fo n digit number.
IF there is problem there is solution
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Hi;
I still can not understand unless I see how you do one. Then how do you do 111 111 111 111 111?
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
Offline
Just for EX
Prime No Even N0 Prime No-Even No=Prime No
427 420 7
431 420 11
433 420 13
437 420 17
439 420 19
443 420 23
449 420 29
451 420 31
457 420 37
461 420 41
463 420 43
467 420 47
Prime No Even N0 Prime No-Even No=Prime No
457 450 7
461 450 11
463 450 13
467 450 17
469 450 19
473 450 23
479 450 29
481 450 31
487 450 37
491 450 41
493 450 43
497 450 47
Prime No Even N0 Prime No-Even No=Prime No
487 480 7
491 480 11
493 480 13
497 480 17
499 480 19
503 480 23
509 480 29
511 480 31
517 480 37
521 480 41
523 480 43
527 480 47
Prime No Even N0 Prime No-Even No=Prime No
517 510 7
521 510 11
523 510 13
527 510 17
529 510 19
533 510 23
539 510 29
541 510 31
547 510 37
551 510 41
553 510 43
557 510 47
Same way
Prime NO Even no Prime NO-Even no= Prime No
5 2 3
7 2 5
11 6 5
13 6 7
17 6 11
19 6 13
23 6 17
29 6 23
37 30 7
41 30 11
43 30 13
47 30 17
53 30 23
59 30 29
61 30 31
67 30 37
71 30 41
73 30 43
223 210 13
227 210 17
229 210 19
233 210 23
239 210 29
241 210 31
251 210 41
257 210 47
263 210 53
269 210 59
271 210 61
277 210 67
281 210 71
283 210 73
293 210 83
307 210 97
311 210 101
313 210 103
317 210 107
2333 2310 23
2339 2310 29
2341 2310 31
2347 2310 37
2351 2310 41
2357 2310 47
2371 2310 61
2377 2310 67
2381 2310 71
2383 2310 73
2389 2310 79
2393 2310 83
2399 2310 89
2411 2310 101
2417 2310 107
2423 2310 113
2437 2310 127
2441 2310 131
2447 2310 137
2459 2310 149
2467 2310 157
2473 2310 163
2477 2310 167
30047 30030 17
30059 30030 29
30071 30030 41
30089 30030 59
30091 30030 61
30097 30030 67
30103 30030 73
30109 30030 79
30113 30030 83
30119 30030 89
30133 30030 103
30137 30030 107
30139 30030 109
30161 30030 131
30169 30030 139
30181 30030 151
30187 30030 157
30197 30030 167
30203 30030 173
30211 30030 181
30223 30030 193
30241 30030 211
30253 30030 223
30259 30030 229
30269 30030 239
30271 30030 241
30293 30030 263
30307 30030 277
30313 30030 283
30319 30030 289
Br
Satish kumar singh
9681572800
Hi satish kumar singh;
Please no more examples. Can you or can't you answer the question put to you in post #21?
I have the computing power but unless you can show what you are doing no progress can be made.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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1. As in Ex you can see result, tragate is to find out prime number.
2. we use to substract Ipn-Pn*=Prime no ( Each and every prime number in fix range).So we may say it is a formula to find out prime number.
3. Pn* you know very well( product of prime number).
4. Ipn I have define above.( it is well define set of odd number)
About your question 111 111 111 111 111 is prime or not
first i will have to find out 10540923 ( product of all prime less then equl to 10540923) can be done
second Ipn i.e ( Ip10540923) set.
Result.. it will give all prime number form 10540923 to its squre.
for ex as in above post
Drawback of formula......
Needed big numers to find out small prime number