Review

zee-f · 2011-09-21 02:30:50

hey i was wondering if i did these correctly

Use the spinner and the following table of experimental data to answer questions 1 and 2. (Note: The smallest section of the circle is 1/16 of the circle. Each of the larger sections are multiples of 1/16.)

(the spinner was here)

(the table was here)

1. What are the experimental probabilities of spinning orange according to the data above? What about green? What about blue? (Remember to explain or show how you get your answer.)

#1- p(orange)=3/16

p(green)=6/16

p(blue)=5/16

because p(desired outcome)= number of times desired outcome occurred / total number of trails

so the number i got the out come is on the top the total witch i got because The smallest section of the circle is 1/16 of the circle

2. Based on the data, does the histogram below represent experimental or theoretical probability? How do you know?

(the histogram was here ))

#2- It represents a theoretical probability. Because in an experimental am conducting an experience am doing. Here the histogram isn't representing what i really got in the data it's representing the number of favorable outcomes.

3. Based on the histogram for question 2, calculate P(red, purple).

3- p(red, purple)=

4. Based on the histogram for question 2, calculate P(red, orange, yellow).

4- p(red,orange,yellow)=

5. Based on the histogram for question 2, calculate P(black, white).

5- p(black,white)=0

Last edited by zee-f (2011-09-21 07:39:07)

bobbym · 2011-09-21 02:36:22

Hi;

1) Is incorrect.

zee-f · 2011-09-21 02:43:15

should the 16 be six thats what i was confused at

bobbym · 2011-09-21 02:46:44

I am getting:

P(orange) = 3 / 16

P(green) = 5 / 16

P(blue) = 3 / 16

zee-f · 2011-09-21 02:52:01

how? am looking at the table

zee-f · 2011-09-21 02:53:07

ooooooooooh the pictures are mixed the table is the third spinner in the middle and the graph is the last

bobbym · 2011-09-21 02:55:10

Yes, which goes with what. I used the spinner, that may not be right.

zee-f · 2011-09-21 02:56:36

nope am spouse to use the data so is am answers correct for number one

bobbym · 2011-09-21 02:57:39

Aren't the histogram and the chart both data?

zee-f · 2011-09-21 03:04:19

yeah they ment the table it was under the question the histogram was under question 2

bobbym · 2011-09-21 03:11:08

So if we are using the table next to the spinner, then
P(orange) = 3 / 30 = 1 / 10

Bob · 2011-09-21 03:59:39

hi zee-f and bobbym,

Question 1 says the table is the experimental data.

recalculating

There were 30 spins according to the table, not 16, so the P(orange) = 3/30 etc.

But the bar chart (not a histogram for reasons of definition but let's not get side-tracked) does not correspond to either the spinner or the table, so question 2 doesn't make sense to me.

3, 4 and 5 are correct for that bar chart.

Bob

Last edited by Bob (2011-09-21 04:04:19)

bobbym · 2011-09-21 04:05:53

Hi;

Theoretical data is derived from the spinner. Experimental from the chart next to the spinner. They are asking her which is closer to the bar chart.

Bob · 2011-09-21 04:10:37

hi bobbym,

But the blue and orange sectors on the spinner are next biggest after green, and equal. But not on the bar chart.

I'm wondering if the bar chart is for a different spinner altogether.

But then how can we tell whether it's experimental or theoretical data.

Only other clue: the bars add up to 16. If we assume the spinner is really badly drawn then perhaps that's why it's theoretical.

?????

Bob

Last edited by Bob (2011-09-21 04:15:57)

bobbym · 2011-09-21 04:16:17

Hi;

I think the bar chart is experimental data because the probabilities are too far off from the spinners probabilities.

Bob · 2011-09-21 04:18:46

I was just going to post that too.

Great minds think alike!

But, oh dear, that was only the first questions ... happy helping .... I'm back to the garage to make props for a show.

Bob

(but it's still not a histogram, he whispered)

Last edited by Bob (2011-09-21 04:20:46)

bobbym · 2011-09-21 04:21:19

Hi;

I do not particularly like the question and even if our answer is right that does not mean we will get marked right.

zee-f · 2011-09-21 07:41:04

hey guys am getting confused am feeling my work is incorrect i edited my info in the picture i cleared were each pic was in the question i said it was out of 16 because they said that The smallest section of the circle is 1/16 of the circle

Bob · 2011-09-21 08:22:31

hi zee-f

I'm on-line now so watch this space/ Help coming up.

Bob

Bob · 2011-09-21 08:23:55

OK you've got a spinner and a table of experimental results.

The experiment is the one you have to use for question 1.

If you add up the frequency column what do you get?

That's the 'number of times spun' figures.

Bob

Last edited by Bob (2011-09-21 08:25:05)

zee-f · 2011-09-21 08:28:09

so i ignore the info they gave me about the 1/16 ?? so its not out of 16 its out of 30 (add up the frequency i get 30)

Bob · 2011-09-21 08:30:03

Yes, for the moment forget 16. You'll need it later but not for question 1.

30 is the number I was hoping for.

Bob

Bob · 2011-09-21 08:34:31

So do you have new answers for question 1 ?

Bob

zee-f · 2011-09-21 08:43:12

#1- p(orange)=3/30

p(green)=6/30

p(blue)=5/30

because p(desired outcome)= number of times desired outcome occurred / total number of trails

i got 30 because i added up the total number of times it was spun i got 30)

thats weird how they added the 16 part this whole because there is no more questions on that graph except 1-5

Bob · 2011-09-21 08:49:18

Answers to question 1 all correct. Excellent!!!

Now we come to question 2. You'll need 16 now.

Start by looking at my post #14.

I took your picture of the spinner and split it up into 16 equal parts.

So please work out the theoretical probabilities for each colour.

These will be out of 16.

Bob

Last edited by Bob (2011-09-21 08:50:12)

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