system of equations

juantheron · 2011-12-12 23:44:35

solve the system of equation

bobbym · 2011-12-13 00:03:49

Hi juantheron;

We can get one equation in one variable.

First thing to do is find real roots by graphing. Using a Cauchy bound we know that all real roots are between -21 and 21.

There are two integer roots x = -1 and x = 2. They are verified by plugging in. We can deflate them out.

A Cauchy bound on this polynomial tells us that all real roots are between -8 and 8. We graph and use Newton's method to get the remaining six roots. They are:

The above process is repeated for each x in the above equations and y and z is isolated and solved for in the same way.

The finished answer is:

juantheron · 2011-12-14 03:44:20

thanks bobbym.

if

Last edited by juantheron (2011-12-14 03:44:40)

bobbym · 2011-12-14 03:58:37

Hi;

Then just take the integers from the solution set.

x = -1, y = -1, z = - 1

x = 2, y = 2, z = 2

juantheron · 2011-12-14 04:47:14

yes got it

thanks

bobbym · 2011-12-14 05:04:37

Hi;

Your welcome. Much less machinery is required to solve this in Z. Graphing and plugging in would have been enough.

Math Is Fun Forum

#1 2011-12-12 23:44:35

system of equations

#2 2011-12-13 00:03:49

Re: system of equations

#3 2011-12-14 03:44:20

Re: system of equations

#4 2011-12-14 03:58:37

Re: system of equations

#5 2011-12-14 04:47:14

Re: system of equations

#6 2011-12-14 05:04:37

Re: system of equations

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