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Three digit no. are formed then what is the probability that middle digit is largest
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Hi;
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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thanks bobbym
but how can you get the answer
would you like to explain here
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Hi;
Look at it like this:
0 or 1 in the middle is impossible for 2 then
{1} 2 {0,1} when 2 is in the middle there can be a 1 on the left and a 0 and 1 on the right 1*2 = 2.
{1,2} 3 {0,1,2} when 3 is in the middle there can be a 1,2 on the left and a 0
,1 and 2 on the right 2*6 = 6.
{1,2,3} 4 {0,1,2,3} when 4 is in the middle there can be a 1,2,3 on the left and a 0
,1,2 and 3 on the right 3*4 = 12.
The series is just a shorthand notation for this process continued till 9 is in the middle.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Thanks bobbym got it (above give process)
but how can you write it in your answer
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Hi;
n = 8. Each term looks this (1*2)+(2*3)+(3*4)+(4*5)+(5*6)+(6*7)+(7*8)+(8*9)= 240
Each term is k(k+1) and there are 8 to be summed.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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thanks got it
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