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A tennis tournament for 2^n players is organised as a knock-out
tournament with n rounds, the last round being the final. Two players
are chosen at random. Calculate the probabilities they meet
a) in the first round
b) in the final
c) in any round
Hi;
Standard book problem straight from my notes copied from some book.
There are
ways to pair off 2^n players. Each round 1/2 of the players are eliminated, First round 2^(n-1) players are paired. Then 2^(n-2) player, 2^(n-3) until we get to the final round when two players are playing.
a)
b)
c)
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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