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find y' for y=e^tan^x^3
I do not know how to find the derivative of this!!
My answer was e^tan^x^3(cot 3x^2) but believe this is totally wrong
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Hi CalculusWANNABE;
I can not understand tan^x^3?
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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tan x to the third power
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So you have this?
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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without tan^3. Its tanx^3 sorry for the confusion
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No problem, is this what you need?
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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yes
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hi CalculusWANNABE
use the chain rule:
f(x)=e^x and g(x)=tan(x^3)
(f(g(x)))'=g'(x)*f'(g(x))
now to get g'(x) we use the chain rule again taking:
h(x)=tan x and t(x)=x^3
(h(t(x)))'=t'(x)*h'(t(x))
Here lies the reader who will never open this book. He is forever dead.
Taking a new step, uttering a new word, is what people fear most. ― Fyodor Dostoyevsky, Crime and Punishment
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Hi;
Use the substitution u = tan(x^3) and then use the chain rule.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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ok thanx so much
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