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Hey everyone! I was wondering if someone can help me out. I have a math project and need a little help:
problem:
You are to pick five numbers ranging from 1 to 56 and a magic number ranging from 1 to 52. What you have to do is come up with possible combination that have a sum totaling 147. How many combinations are there? What are the combinations?
I was wondering if can help me start the problem ..... and is there a way to do this on excel or an online program I can use..
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Hi aegiziano1,
Are the 5 numbers distinct?
"Believe nothing, no matter where you read it, or who said it, no matter if I have said it, unless it agrees with your own reason and your own common sense" - Buddha?
"Data! Data! Data!" he cried impatiently. "I can't make bricks without clay."
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Hi all;
How many combinations are there?
Generating functions can do this.
What are the combinations?
Unless there are only a few then you will need a computer.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Hi gAr,
Yes sorry the 5 are distinct. No repeating numbers.
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Hi aegiziano1;
How about the magic number? Is it distinct too?
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Gar,
Yes in the fact that you only pick one magic number but may not be distinct from the other five numbers.......
magic# magic#
random ex: 4 15 25 38 27 4 or 5 9 13 32 45 20
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Hi aegiziano1;
I have everything I need except for one thing. You say combinations, so you mean order does not count, For instance:
1,2,3,4,5,137 is the same as 137,2,3,1,5,4.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Gar,
Yes order does not matter for the 5 number, but the magic number is at the end ....so technically order matters lol... let me know if this is confusing.......... the problem is like picking numbers for the lottery, for example: Mega Million, and the numbers you pick have to add up to 147
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Hi;
So we have _ _ _ _ _ (magic number)?
Order for the first 5 does not count and magic number on the end. Okay, I think I understand.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Yes you got it!... Sorry for the confusion ... should have explained it better
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Hi aegiziano1;
I am getting:
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Hi bobym,
Whats your thought process behind the 42113?
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In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Hi all,
bobbym, 42113 is okay for first five digits and a sum of 147. Aren't we supposed to consider the 6th digit also for totaling?
That way, I get:
"Believe nothing, no matter where you read it, or who said it, no matter if I have said it, unless it agrees with your own reason and your own common sense" - Buddha?
"Data! Data! Data!" he cried impatiently. "I can't make bricks without clay."
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Hi gAr;
Yes, you are right that is a clumsy error on my part.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Hi bobbym,
Okay. It happens to me too.
"Believe nothing, no matter where you read it, or who said it, no matter if I have said it, unless it agrees with your own reason and your own common sense" - Buddha?
"Data! Data! Data!" he cried impatiently. "I can't make bricks without clay."
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Hi;
I do not what the heck I was thinking of. Thanks for spotting that! I guess I got too caught up on trying to find a formula. Of course, I had the wrong GF because I was solving the wrong problem!
Hi aegiziano1;
Use gAr's work in post #14, sorry for the error.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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You're welcome!
I'll take a break, see you later.
"Believe nothing, no matter where you read it, or who said it, no matter if I have said it, unless it agrees with your own reason and your own common sense" - Buddha?
"Data! Data! Data!" he cried impatiently. "I can't make bricks without clay."
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See you later,my friend.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Thanks guys I appreciate it!
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Two of us worked hard on this. One of us solved it and the other one worked like a washing machine...
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Enjoyed it.
Hope you wouldn't require the list, which takes about 28 MiB.
"Believe nothing, no matter where you read it, or who said it, no matter if I have said it, unless it agrees with your own reason and your own common sense" - Buddha?
"Data! Data! Data!" he cried impatiently. "I can't make bricks without clay."
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Dear All
I need help on solving a problem .
I want to arrange numbers
Where there are three names on the vertical side like
W. D. A
1
2
3
I want to perm or combine where there are not more than one digit on the vertical role.
Eg.
W. D. A
1. X
2. X
3. X
Or
W. D. A
1 x
2. X
3. X
Any help please?
Many thanks
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Hi Labodmin;
Welcome to the forum.
I want to arrange numbers
How many numbers are there? Are the numbers different?
If we use the numbers 1,2,3 then we get
I used zeros as space holders so it would line up nice. That is 162 ways.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Many thanks
The numbers am looking to perm will be like
W1,w2,w3,1d,2d,3d,1a,2a,3a
The table is like eg
W. D. A
1 X
2. X
3. X
Eg of this second table will be wrong
W D. A
1
2
3. X. X. X
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