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Prove the following.
1. cotAcotB + cotAcotC + cotBcotC = 1
Integration problem
2. Given Integrate of (e^2x - e^-2x)/(e^2x + e^-2x)=1/2 ln(e^2x+e^2x)
Find integration of (e^2x)/(e^2x + e^-2x)
Thanks very much.
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HI lqq889
For Q1. is there a restriction such as A + B + C = 2PI ?
Bob
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you! …………….Bob
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I think, YES, because I've check the expression with unrestricted values and it doesn't come to 1
note:
if A + B + C = 2pi then sin(B+C) = sin(2pi - A) = - sinA and cos(A) = cos(2pi - B - C) = cos(B+C)
Bob
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you! …………….Bob
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HI lqq889
For Q1. is there a restriction such as A + B + C = 2PI ?
Bob
Thanks,
A, B, and C are angles of triangle ABC.
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Q2.
Call the given integration equation A.
Form and evaluate this integral B
Then consider A + B.
Bob
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you! …………….Bob
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bob bundy wrote:HI lqq889
For Q1. is there a restriction such as A + B + C = 2PI ?
Bob
Thanks,
A, B, and C are angles of triangle ABC.
It doesn't change almost anything except a few signs.
Here lies the reader who will never open this book. He is forever dead.
Taking a new step, uttering a new word, is what people fear most. ― Fyodor Dostoyevsky, Crime and Punishment
The knowledge of some things as a function of age is a delta function.
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Can give me more details of doing question 2, thanks
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Coming up. Stay on line!
Bob
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you! …………….Bob
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If you do A + B
you will get
which is twice the required integral.
Bob
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you! …………….Bob
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Hi llq889
Here is for the first one:
Here lies the reader who will never open this book. He is forever dead.
Taking a new step, uttering a new word, is what people fear most. ― Fyodor Dostoyevsky, Crime and Punishment
The knowledge of some things as a function of age is a delta function.
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hi Stefy,
Wow! You've become legendary! I'm most impressed!
Now, about your proof. Please compare with mine (post 3).
We seem to have a difference over sin(B+C) = + or - sin A
aarrh, wait a minute, I see why. I've got A + B + c = 2pi and the OP posted later that A + B + C = pi.
That seems to cover it.
I've also just read your earlier post.
It also confirms my suspicion this morning that it might be possible to prove for more than one total.
Bob
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you! …………….Bob
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Hi Bob
Thank you,but however many ppst I had it will not mach up to your posts.
Yes,I said rlearlier that the sign would change,but I am wondering-do you mean it can be proved for a general polygon?
Here lies the reader who will never open this book. He is forever dead.
Taking a new step, uttering a new word, is what people fear most. ― Fyodor Dostoyevsky, Crime and Punishment
The knowledge of some things as a function of age is a delta function.
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Hi Bob and stefy,
Thanks two of you for the great explanation for the question 1, I had understood, but I still don quite understand the question 2, can someone please explan more detail for me, thanks.
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hi
You are given an integral of the form:
You are asked for
So, how to get rid of the 'Q' on the top of the fraction?
Find
Now, to get rid of the Q, add A and B:
Bob
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you! …………….Bob
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Thanks Bob, I am understood.
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You're welcome!
Bob
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you! …………….Bob
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Hi Bob
I was thinking the other day about giving you the nickname "K5".
Here lies the reader who will never open this book. He is forever dead.
Taking a new step, uttering a new word, is what people fear most. ― Fyodor Dostoyevsky, Crime and Punishment
The knowledge of some things as a function of age is a delta function.
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