Simplifying Monomials Help (Algebra 2)

njkidd · 2005-12-30 09:54:12

1) (4xy³)-² (5x-³y^4)³

2) y-2 / y^5-3y²-20

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1) i have 2000/x^11y^6

2) i have y^4-3y^2+10

Thanks in advance.

krassi_holmz · 2005-12-30 10:16:02

1)

Last edited by krassi_holmz (2005-12-30 10:17:57)

krassi_holmz · 2005-12-30 10:21:21

2) It is not monomial It cannot be simplified:

deepu · 2005-12-30 10:37:08

Hi

1) 1/(4xy^3)^2 * 125x^-9y^12

= (125y^6)/16x^11

2) Let us first divide (y^5-3y²-20) by (y-2)

The quotient will be y^4 + 2y^3 + 4y^2 +5y+10

which means that

(y-2)(y^4 + 2y^3 + 4y^2 +5y+10) = y^5-3y²-20

Therefore,

y-2 / y^5-3y²-20

=y-2/ (y-2)(y^4 + 2y^3 + 4y^2 +5y+10)

(y-2) in the numerator and denominator gets cancelled and the answer will be

= 1/(y^4 + 2y^3 + 4y^2 +5y+10)

Last edited by deepu (2005-12-30 10:40:26)

krassi_holmz · 2005-12-30 11:35:33

Yes, Deepu, you're right.

njkidd · 2005-12-30 13:08:38

Thanks, i got them now.

deepu · 2005-12-31 01:36:58

Hi krassi Holmz

Thanks for helping

krassi_holmz · 2005-12-31 01:43:05

Hi. Happy New Year!!!

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