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There are 6 couples (12 people). 4 people are selected at random. What is the probability that exactly one couple will be selected
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Hi;
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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P(exactly 1 pair selected)=1- ( P(no pairs selected) + P(2 pairs selected) )
Here lies the reader who will never open this book. He is forever dead.
Taking a new step, uttering a new word, is what people fear most. ― Fyodor Dostoyevsky, Crime and Punishment
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Thanks Bobbym and anonimnystly
Yes Bobbym you are Right
but would you like to explain it to me
Thanks
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Hi;
You can choose 2 pairs in
You can choose 4 cards in
So the probability of 2 pairs is 1 / 33
You can have no pairs in
ways.
So the probability of 0 pairs is 16 / 33
The complement is the probability of 1 pair.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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