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Let their be a triangle ABC with sides a opposite to A, b opposite to B and c opposite to C. It is right angled at C. If p is the perpendicular from C to AB.
Then Is the following true? If yes, how?
'And fun? If maths is fun, then getting a tooth extraction is fun. A viral infection is fun. Rabies shots are fun.'
'God exists because Mathematics is consistent, and the devil exists because we cannot prove it'
I'm not crazy, my mother had me tested.
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hi Agnishom
Yes it is.
outline of proof follows.
Let AD = x and DB = y as shown in diagram. => x + y = c
Use Pythagoras together with ab = pc in eqn 1
The rest I leave to you.
Bob
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you! …………….Bob
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Putting ab = pc in eqn1:
It was indeed a great one
'And fun? If maths is fun, then getting a tooth extraction is fun. A viral infection is fun. Rabies shots are fun.'
'God exists because Mathematics is consistent, and the devil exists because we cannot prove it'
I'm not crazy, my mother had me tested.
Offline
Pages: 1