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Hi all. I think i'm making a mistake somewhere as the matrix I get after multiplying doesn't seem to be invertible and the next question is to find A^-1. Is this the right way to do this?
Thanks in advance
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Hi;
I am getting:
which can be inverted.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Hi Bobbym any idea where I made a mistake?
Thanks a lot
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Hi;
Your mistake is in line 3. Check how you multiplied those matrices.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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You multiplied the matrices incorrectly
Never mind, bobbym was faster.
hi Deon588
Your inverses are correct, so then you need to do the multiplying.
(AB)C = A(BC) for matrices so you have a choice of which pair you multiply first. But you must preserve order.
eg if AB = D you then do DC not CD.
I'm going to do these both ways in case I choose the way you didn't (if you see what mean)
or
Bob
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you! …………….Bob
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and you should find that inverse A = E3.E2.E1
This would be a good check that you have inv A right and that your multiplying is OK.
Bob
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you! …………….Bob
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Hi Bob thanks a lot for all the effort. I had no idea how to multiply more than 2 matrices so I tried doing all 3 at once...
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Hi Deon588;
Always break a big problem down into smaller pieces that you know how to do. This top down design is very common in programming. You knew how to do 2 matrices.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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hi Deon588
I know the rule for multiplying two matrices. I dareay you could devise a rule for three but it would be hard to remember. So two at a time is simplest.
You shouldn't assume that matrices can be swopped around like numbers but associativity { (AB)C = A(BC) } does work.
Beware: commutativity doesn't. { AB ≠ BA }
Did you try my practice suggestion?
and you should find that inverse A = E3.E2.E1
This would be a good check that you have inv A right and that your multiplying is OK.
Bob
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you! …………….Bob
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Yes that was also the next question in the exam paper I did, worked out perfectly at the end
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Bob
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you! …………….Bob
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