Modulo

Leroy · 2012-10-25 22:29:20

How do i solve these
5 mod 2+2i
4+5i mod 3
3+i mod 1+i
i mod 3
56 mod 5i

bobbym · 2012-10-25 22:46:56

Hi Leroy;

For 5 mod 2+2i;

So the answer is 1.

For 4+5i mod 3;

So the answer is 1 - i.

Leroy · 2012-10-25 23:36:06

I didn't really understood the first method and it seems to me the second one could be (4+5i)-3(1+i)=1+2i

bobbym · 2012-10-25 23:40:30

Hi;

That is not the correct expression. Mathematica confirms what I did in post #3.

Ronald · 2012-10-25 23:45:01

Ok,but could you explain the method to me?

bobbym · 2012-10-25 23:59:32

Hi;

I am just plugging into a formula:

For a mod n

I have been interpreting the int as the greatest integer.

I would say to be careful with the work done above. I can find no standardization for that formula for complex numbers. As a matter of fact some say floor or int are not defined for complex numbers. Others define them differently than Mathematica does.

zetafunc. · 2012-10-26 03:59:18

Interesting, I never thought about modular arithmetic with complex numbers.

Leroy · 2012-10-26 04:25:31

I think,as complex number is also a number,so it should have all properties of normal number-mod,factorial,floor,ceil,ratio,integer part,...

bobbym · 2012-10-26 04:39:50

Not necessarily, there are differences. For one thing the mod function is different.

Math Is Fun Forum

#1 2012-10-25 22:29:20

Modulo

#2 2012-10-25 22:46:56

Re: Modulo

#3 2012-10-25 23:36:06

Re: Modulo

#4 2012-10-25 23:40:30

Re: Modulo

#5 2012-10-25 23:45:01

Re: Modulo

#6 2012-10-25 23:59:32

Re: Modulo

#7 2012-10-26 03:59:18

Re: Modulo

#8 2012-10-26 04:25:31

Re: Modulo

#9 2012-10-26 04:39:50

Re: Modulo

Board footer