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Hi;
The numbers am looking to perm will be like
Unless you are through with the question I want to know exactly what numbers you want to permute.
As I understand it you do not want 2 in the same row.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Hi they are 1,2,3,4,5,6 on the vertical row and W D A on the horizontal row
what you did looks similar
Its like football pool games where 1,2,3,4,5,6 will be the teams
Eg will be
W D A
1 x
2 x
3 x
4 x
5 x
6 x
Many thanks
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Hi;
Okay, I will work on it and post if I have a solution.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Hi Bobbym
What you have send looks good.
l will change it round to suit what l need it for.
What formula did you use so that l can follow the same trend to organise larger number like 1,2,3,4,5,6,7,8,9,10?
Best regards
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Hi;
No formula. And for bigger numbers there may be a lot more permutations, thousands or millions. A formula would only tell how many there are, it would not show what they are.
Using a method, I come up with
That means there are 524880 ways to permute those 6 numbers in those 18 boxes.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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hello, l am looking at the first numbers you sent:
0 0 1
0 0 2
0 0 3
which were all 162 ways.
if l was to do the same for 1,2,3,4,5,6 how many ways will it be all together and can you also help me organise them please?
Many thanks
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Hi Labodmin;
There are 524880 ways to arrange them! That is a very large number.
That is for your problem in post #27. It is quite easy to get the number but to arrange them will require a computer. Do you program?
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Hi many thanks for the reply.
I don't program .
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Hi;
Okay, let me know if I can do something else.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Hi gAr and bobbym,
Sorry for such a late response.. After our last postings (post 22) I have been crammed with Finals, Papers, Projects and what not.... The project that you guys helped me on was a success , thanks again!...
.. I was wondering (just out of curiosity) since the file would be tremendously large to show all possible solutions, if there is an actual way to break up the solutions to accommodate the file size.
Last edited by aegiziano1 (2012-02-26 07:50:49)
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Break up the solutions? I am not following you.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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I mean instead of the list of 1,748,533 solutions on one single file, is it possible to put the soultions on multiple files?
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Hi;
I would say so. You could also zip it up to make it smaller.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Hi aegiziano1,
As a 7z compressed tarball, it's around 514KiB.
"Believe nothing, no matter where you read it, or who said it, no matter if I have said it, unless it agrees with your own reason and your own common sense" - Buddha?
"Data! Data! Data!" he cried impatiently. "I can't make bricks without clay."
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hey guys ,
I was trying to figure out how to write the code to generate a list for the following code.... let me know if you guys can help?
the question was pick 5 number 1-56 ( No repeats) and an extra number 1-52
#include <cstdlib>
#include <iostream>
using namespace std;
int main()
{
int cnt = 0;
int x1,x2,x3,x4,x5,y;
for (x1=1;x1<57;x1++)
{
for (x2=x1+1;x2<57;x2++)
{
for (x3=x2+1;x3<57;x3++)
{
for (x4=x3+1;x4<57;x4++)
{
for (x5=x4+1;x5<57;x5++)
{
for (y=1;y<53;y++)
{
if (x1+x2+x3+x4+x5+y == 147)
{
cnt++;
}
}
}
}
}
}
}
printf("%d",cnt);
system("PAUSE");
return 0;
}
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What answer did you get when you put a counter in the middle of that?
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
Offline