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9pq < 6pq +6(1-p)(1-q). Implying that 3pq/(1-p)(1-q) < (less than or equal to) 2
PLEASE explain this somebody! I don't understand how this works? Does it not equal 3<6(1-p)(1-q)?
Please walk me through this. Thanks.
Hi BarandaMan;
Do you mean
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Yes I do! That is what the answer says but i do not understand how it gets past the 'implies' after rearranging
Hi;
Subtract 6pq from both sides.
Divide both sides by 3.
Divide both sides by (1-p)(1-q) provided that p,q are both less than 1.
I do not know where the 3 comes from in your question.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Hey!
That is exactly what I got! Thank you. That is why I am confused, because the 3pq I posted it in the ANSWER BOOK. Which is why I am confused by this!
It cannot be the answer from the inequality!
Hi;
The answer book? What is that?
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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I did the question from a book, and in the back ith as the answers. The first line of my original post shows what the answer is in the textbook. It must be wrong, I will write a letter. It is simple inequality I thought... must be printing error.
I would think it is a typo.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
Offline
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