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The p-norm of a vector(in 2d) is (|x|^p+|y|^p)^(1/p) my question is can p be 0,fraction or nagetive?
There are 10 kinds of people in the world,people who understand binary and people who don't.
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If I recall correctly, p can be any real number apart from 0.
Actually, p must be a real number greater or equal to 1.
Here lies the reader who will never open this book. He is forever dead.
Taking a new step, uttering a new word, is what people fear most. ― Fyodor Dostoyevsky, Crime and Punishment
The knowledge of some things as a function of age is a delta function.
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Why isn't nagetive number or fractions<1 allowed?
There are 10 kinds of people in the world,people who understand binary and people who don't.
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Because it wouldn't be a norm (it would give zero values if any of the coordinates is 0).
Here lies the reader who will never open this book. He is forever dead.
Taking a new step, uttering a new word, is what people fear most. ― Fyodor Dostoyevsky, Crime and Punishment
The knowledge of some things as a function of age is a delta function.
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Oh,thanks.
There are 10 kinds of people in the world,people who understand binary and people who don't.
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