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Help me to solve this plz!
If
g(x)=2-5f(3x) & f'^(-1)(0)=5
g'^(-1)(2)=?
A)-0.33
B)0.66
C)0.33
D)-0.66
tnx
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hi apiece
Welcome to the forum.
g(x)=2-5f(3x)
OK. I get that.
f'^(-1)(0)=5
Do you mean the inverse function for f evaluated at x = 0, is 5 ?
The second image doesn't say this.
g'^(-1)(2)=?
Do you mean differentiate g, construct the inverse function, then evaluate it at x = 2 ?
That's not what you've got in the third image.
And now I think about it, by writing function^-1 do you mean the inverse function at all, or the reciprocal function
eg. does sin^-1 mean arcsin or 1/sin ?
Bob
Last edited by Bob (2013-03-20 06:21:45)
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