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I am stumped again.
Find the equation of line L in standard form. L is parallel to y=1/3x.
I am not sure why I am thrown off. It shows line L with a point of (2,4)
I have y=-x+6 and I know that can't be correct because the slopw is 1/3 so is it y=-1/3x+6
I am really confused.
Please help to see what the answer is and why so that I can understand.
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hi Mom,
To be parallel it must have the same gradient, ie. 1/3
So y = (1/3)x + something..
(2,4) => 4 = (1/3)2 + something => something = 4 - 2/3
Bob
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you! …………….Bob ![]()
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Well, we know that it must be of the form y=1/3 x+n, so we just substitute x=2 and y=4 and solve for n. Can you do that?
Last edited by anonimnystefy (2013-05-08 06:59:03)
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Im still lost but thanks Bob
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http://www.mathsisfun.com/equation_of_line.html
and
http://www.mathsisfun.com/data/straight_line_graph.html
Bob
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you! …………….Bob ![]()
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Im still lost but thanks Bob
On which part are you lost? Thank you! ![]()
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simple, just note that it goes thru (0,0), so subtract from y and and x the 2 and the 4.
(y-4) = (1/3)(x-2)
that's all there is to it.
very simple.
the end.
lol. ![]()
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