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Calculate the surface integral:
∫ ∫ with s on bottom. F dot dS where F (x,y,z) = = (2x + y + z ; x + 2y + z ; x + y + 2z)
where S is the surface of the box bounded by the planes x = 0, x = 1, y = 0, y = 4, z = 0, z = 5
I used the divergence theorem and got 120.
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Some clarification
Calculate the surface integral seen there:
http://latex.codecogs.com/gif.latex?\int%20\int_{S}%20F\cdot%20d\mathbf{S}
when:
http://latex.codecogs.com/gif.latex?F(x,y,z)%20=%20(2x%20+%20y%20+%20z%20;%20x%20+%202y%20+%20z%20;%20x%20+%20y%20+%202z)
Thanks for bobbym for telling me about codecogs to make the stuff look better.
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Hi;
You can take codecog's output and put it between the math tags to create latex here.
Your answer of 120 by the divergence theorem is what I am getting. Hopefully, the conditions of that theorem have not been violated.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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