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mn^-9m^30/m^0m^23
I get m^8/n^9???? am I close?:/
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I think the question should be
[(m)*(n)^-9]*[m^30]/[m^0]*[m^23]
If thats the question, your answer is correc t.
It appears to me that if one wants to make progress in mathematics, one should study the masters and not the pupils. - Niels Henrik Abel.
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