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Maybe its the same thing. I am not sure.
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I could also write the routines to generate a problem in Mathematica with exact arithmetic. Leaving Geogebra out. The error would diminish greatly.
Did you have a fixed n you needed to be solved or were you just seeing what could be done?
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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No, only I want to see...just being curious!
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Hi;
Okay, I understand.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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To be honest, I want to know if by having 2n equations
(of the previous form==leading coef.+ 1 point of the polynomial)
I can define the intersection point of the n degree polynomials.
You and anomnimistefy prove that for the case of n=2, n=3 the previous case stands.
I think it stands for every n.
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Each set of polynomials of n degree can only intersect at n points. Each point will have 2 variables x and y. You will need 2n equations to solve for them.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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I thought we already got to this conclusion before.
Here lies the reader who will never open this book. He is forever dead.
Taking a new step, uttering a new word, is what people fear most. ― Fyodor Dostoyevsky, Crime and Punishment
The knowledge of some things as a function of age is a delta function.
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The evidence supports this but there are practical considerations.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Hey bobby m,
Do you know if the set of equations that were talking about can be solved over Galois Fields?Or where to search?
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If you mean solved modulo 1...n, then Mathematica might be able to handle the job.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Yes I meant a Finite feild generated by a prime n or an irreducible polynomial.
I am not sure that is solvable if the equations of the set are nonlinear i.e. te polynomials are of 2-degree 3- etc...
Last edited by Herc11 (2013-07-19 19:55:22)
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Hi;
Do you have a worked example?
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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No..It is not easy to test it. I have written in C a galois field multiplier and divider for an irreducilbe polynomial of degree 128.
The addition is simply an xor.
The equations are the same that I was posted in previous posts.
I google it and the results that wre obtained confused me. e.g. I tried to read the following thesis but with no result.
If i undersstood correctly the problem is not easily solvable but I am not sure that this thesis copes the same problem as mine
https://openaccess.leidenuniv.nl/bitstream/handle/1887/4392/Thesis.pdf?sequence=1
Last edited by Herc11 (2013-07-19 21:56:23)
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Hi;
Reading the pdf now.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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I think that when the set of equations is constituted by polynomials of degree-n, an unknown
will come up.I dont know how
can be computed over GFs.Offline
Isn't that covered in his "power extraction algorithm?" Of course, he has gone on and on with his existence proofs but I do not see an implementation so far.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Whats this?I ve never heard it. Can this solve the aforementioned problem?
You give me hope!
Last edited by Herc11 (2013-07-20 00:32:35)
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He mentions it in the pdf you provided.
You should not have hope yet. Highbrows like him rarely explain anything. The chance that he will provide an example that a lowbrow like me can follow is 1 in 10000.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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If we try a different approach and instead replacing the
to the formula we writethen the formula will be e.g for 3 degree polynomials
So If again we know
we need a ste of 2x3=6 such polynomials to solve the system and the system remains linear i.e. to get the afterwards that we have definedwe can solve
and recover the missing intersection points.
So it seems that it can be solved over GF. I think...
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Wouldn't a0, a1, a2,... all have to be members of the GF?
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Yes all are members of the GF.
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Hi;
How can you be sure?
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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About what?
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That the a0, a1, a2... will all be integers let alone mebers of that set?
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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All the variables known and unknown will be elements of a Galois Field. Multiplication Division, addition(=substraction) will be defined over the GF. The result of the operations will be GFs too. They are not integers but elements of the GF. I mean that alla the problem will be defined and solved over the GF.
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