Math Is Fun Forum

mukesh

Member

Registered: 2010-07-18

Posts: 31

Arithmetic Means

show that the sum of the arithmetic means between two given quantities ,equidistant from the beginning and the end is constant.

Bob

Administrator

Registered: 2010-06-20

Posts: 10,621

Re: Arithmetic Means

hi mukesh

I am not very clear about what is variable and what fixed here.  Let's see if I can sort this out.

Let beginning = b
end = e

first quantity = a
second quantity = c

equidistant => a - b  = e - c

=> a + c = e + b

So, if e and b are fixed it should be easy for you to finish this off. 

Bob

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Children are not defined by school ...........The Fonz
You cannot teach a man anything;  you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you!  …………….Bob

mukesh

Member

Registered: 2010-07-18

Posts: 31

Re: Arithmetic Means

sir here beginning and last numbers are constant,fixed.
plse explane in brief ,i m in trouble

Bob

Administrator

Registered: 2010-06-20

Posts: 10,621

Re: Arithmetic Means

That's what I was assuming.

b + e = constant => a+ c is constant.

All you need to fill in is the arithmetic mean.  Do you know what that is?

Bob

---

Children are not defined by school ...........The Fonz
You cannot teach a man anything;  you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you!  …………….Bob