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#1 2013-11-23 23:37:06
- BenLee
- Guest
Need Logarithm Help.
Hello I have been trying this questions forever to no avail. Could anyone help me?
A. Using the laws of logarithms, simplify x-0.45 = 0.521 and evaluate for x [5 marks]
B. Find the fifth root of 600 using logarithms. [4 marks]
#2 2013-11-23 23:45:41
- bobbym
- bumpkin
- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 109,606
Re: Need Logarithm Help.
Hi;
A. Using the laws of logarithms, simplify x-0.45 = 0.521 and evaluate for x [5 marks]
Why do you need logarithms to solve a linear equation?
Add .45 to both sides.
For B, what are you allowed to use? A calculator? A log table?
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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#3 2013-11-23 23:48:32
- Benlee
- Guest
Re: Need Logarithm Help.
Wow... Didn't know it was that simple... haha, but it is an assignment and unfortunately I need to use logarithm for it. I was thinking of putting "lg" on both sides, but not sure if that's the correct way.
#4 2013-11-23 23:52:43
- bobbym
- bumpkin
- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 109,606
Re: Need Logarithm Help.
Do you have the right problem?
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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#5 2013-11-23 23:59:43
- BenLee
- Guest
Re: Need Logarithm Help.
Apologies, knew something was not right. I typed wrongly.
A. Using the laws of logarithms, simplify x^-0.45 = 0.521 and evaluate for x [5 marks]
#6 2013-11-24 00:03:11
- bobbym
- bumpkin
- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 109,606
Re: Need Logarithm Help.
x^-0.45 = 0.521
When you take the log of both sides what do you get?
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
Offline
#7 2013-11-24 00:08:24
- BenLee
- Guest
Re: Need Logarithm Help.
lg x^-0.45 = lg 0.521
Is this right? Seems weird to me.
#8 2013-11-24 00:14:15
- bobbym
- bumpkin
- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 109,606
Re: Need Logarithm Help.
That is correct and what is log(x^(-.45)) ?
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
Offline
#9 2013-11-24 00:18:39
- BenLee
- Guest
Re: Need Logarithm Help.
I got -0.45 lgx = lg 0.521
lg x = 0.629
Is that the answer or do i need to move the lg to make x the subject? o.o
#10 2013-11-24 00:29:25
- bobbym
- bumpkin
- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 109,606
Re: Need Logarithm Help.
What did you get for lg 0.521?
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
Offline
#11 2013-11-24 00:32:37
- BenLee
- Guest
Re: Need Logarithm Help.
I got -0.283162276 and i divided that by -0.45 to get 0.629
#12 2013-11-24 00:39:42
- bobbym
- bumpkin
- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 109,606
Re: Need Logarithm Help.
That is correct. So what do you have left?
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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#13 2013-11-24 00:41:16
- BenLee
- Guest
Re: Need Logarithm Help.
I have lg x = 0.629 left.
Should i make x the subject now or is that the answer? o.o
#14 2013-11-24 00:42:17
- bobbym
- bumpkin
- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 109,606
Re: Need Logarithm Help.
What is the inverse of log(x)?
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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#15 2013-11-24 00:45:16
- BenLee
- Guest
Re: Need Logarithm Help.
Is it log x^-1?
#16 2013-11-24 00:45:47
- bobbym
- bumpkin
- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 109,606
Re: Need Logarithm Help.
You are using the common log?
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
Offline
#17 2013-11-24 00:49:04
- BenLee
- Guest
Re: Need Logarithm Help.
I guess so, the other log thingy is "ln"
#18 2013-11-24 00:52:47
- bobbym
- bumpkin
- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 109,606
Re: Need Logarithm Help.
When we say log(3) we mean what power must 10 be raised to, to get 3.
So what do you think now is the inverse of log? You should get raising 10 to the power of.
So taking 10^ of both sides what do you get?
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
Offline
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