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How can I find out the value of the Fourier series
at t=(2-pi)?
If t=(2-pi) had been a point where the function is continuous I know the value of the Fourier series would be the same as the function but since this a point which is not continuous, how can you find out the value of the Fourier series at that point?
Also note that this is a 2pi-periodic even function, where
f(t) = 0 when 0 < t < pi-2
f(t) = pi when pi-2 < t <pi
(Draw the graph and you will see what I mean by continuous).
Actually for this question, a simple correct answer would do to start with.
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