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if z=2+ia y=b+i2 x=0 are vertices of an equilateral triangle such that a, b are
real numbers such that a, b ∈(0,1) then which of the following is true?
1.)a=b=4+2sqrt(3)
2.)a=2, b=sqrt(3)
3.)a=sqrt(3),b=2
4.)a=b=-1+sqrt(2)
i found that a=b=4+2sqrt(3) or 4-2sqrt(3) but due to the condition a,b ∈(0,1) i choose 4-2sqrt(3) but it's not even in the options the answer sheet says that the right answer is 4.)
why is it so?can anybody please help me out on this one
"The man was just too bored so he invented maths for fun"
-some wise guy
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hi gourish
I'm getting the same result as you.
I wonder if there's a typo with the question, because 3 answers can be rejected without calculation, just using a, b in (0,1).
Bob
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you! …………….Bob
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thanks good to know that....
"The man was just too bored so he invented maths for fun"
-some wise guy
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Hi
Did you follow what Nehushtan said about the integration question?
Bob
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you! …………….Bob
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no, i did not know can you send me the link?
"The man was just too bored so he invented maths for fun"
-some wise guy
Offline
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you! …………….Bob
Offline
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