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We have two spheres with centers (x_1, y_1, z_1) and (x_2, y_2, z_2). And radii r_1 and r_2.
What is the volume of solid intersection of these two spheres?
I am not sure how to approach this question.
I know that a point will belong to the solid iff:
It should be something like a sum of all points which satisfy the inequality:
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well choose only try choosing only a single plane like the x-y plane as the base and then find the area that the solid cuts in that plane and then multiply it with the "height" that the solid has covered in the z axis... that's my approach but even i do not know what formula's are to be applied so i am pretty much going on intuition
"The man was just too bored so he invented maths for fun"
-some wise guy
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hi White_Owl
If you can introduce new axes so that the x axis is along the line of centres then I think a volume of revolution becomes possible. The intersection is a (circular) vertical plane so you would just need to do the two parts separately.
Bob
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you! …………….Bob
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bob bundy,
you mean to draw a line through centers of the spheres, and look at this line as at a 'new' x-axis? Yes, this will work, thank you.
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