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Fire works are shot upward with an intial velocity of 125 feet per second from a platform 3 feet from ground. how lonh does the rock take to hit the ground?
I've gotten
16t^2= 125 + s and get 31.25 seconds?? am I close???
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The relevant formulae
are
(1) v=u+at
(2) S = ut + ½at²
and (3) v²=u²+2aS
Where S=displacement, u=initial velocity, v=final velocity, t=time, a=acceleration.
When a projectile is fired upward, the gravitational force of earth tends to retard the motion of the projectile. The acceleration due to gravity,
g=9.8 m/s².
Since this acts against the upward motion, a has to be taken as negative.
Moreover, all the quantities should be converted to SI Units.
With these hints, please try to solve the problem.
It appears to me that if one wants to make progress in mathematics, one should study the masters and not the pupils. - Niels Henrik Abel.
Nothing is better than reading and gaining more and more knowledge - Stephen William Hawking.
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